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Enter equation to graph, e.g. y=3x^2-1

Depdendent Variable

Number of equations to solve:

Equ. #1:

Equ. #2:

Equ. #3:

Equ. #4:

Equ. #5:

Equ. #6:

Equ. #7:

Equ. #8:

Equ. #9:

Solve for:

Enter inequality to solve, e.g. 2x+3>4

Enter inequality to graph, e.g. y<3x^2-1

Dependent Variable

Number of inequalities to solve:

Ineq. #1:

Ineq. #2:

Ineq. #3:

Ineq. #4:

Ineq. #5:

Ineq. #6:

Ineq. #7:

Ineq. #8:

Ineq. #9:

Solve for:

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Multiplying and Dividing With Square Roots

Remember the rules for multiplication and division with algebraic square roots:

Property 1:

Property 2:

where ‘a’ and ‘b’ stand for any valid mathematical expression.

Examples with solutions

Example 1:

Simplify

solution:

as the final answer.

Example 2:

Simplify

solution:

Divisions can be written as fractions, so the methods of the last two examples can be used here.

as the final answer.

Example 3:

Simplify

solution:

This is really more of a “rationalize the denominator” problem than it is a dividing problem. We get

as the final, simplest result.

Example 4:

Simplify

solution:

as the final simplified result with the denominator rationalized.

Example 5:

Expand and simplify the product:

solution:

The final result here may be a bit of a surprise. Basically, we are asked to multiply one trinomial by another, and simplify the result. The multiplication step is a bit tedious, but you are well familiar with the method:

as the final simplified answer. Notice that all of the square root terms in the second last line have cancelled out, because they each occur in pairs of opposite sign.

If you attempt to factor the trinomial x² + 8x + 10 into a product of two binomials there, you will fail. (Why?)

This example here shows that x² + 8x + 10 can be “factored” into a product, but it is a product of two trinomials (hardly a simplification!) and those trinomials involve the square root of a number. You can see that the systematic trial and verification method we used to factor trinomials into products of binomials will not work to get this factorization.